A hydrogen atom in the ground state absorbs a 12.75-eV photon. To what level is the electron promoted? (The ionization energy of hydrogen is 13.6 eV).
A) n = 2
B) n = 3
C) n = 5
D) n = 4

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The Answer of A hydrogen atom in the ground state absorbs a 12.75-eV photon. To what level is the electron promoted? (The ionization energy of hydrogen is 13.6 eV).
A) n = 2
B) n = 3
C) n = 5
D) n = 4

A Hydrogen Atom in the Ground State Absorbs a 12