A quantum of radiation has an energy of 1.3 keV. What is its frequency? (h = 6.63 *10^-³⁴ J.s and 1 eV = 1.60 *10^-¹⁹ J) A) 6.3 *10¹⁷ Hz B) 3.1 * 10¹⁷ Hz C) 4.8 * 10¹⁷ Hz D) 7.2 * 10¹⁷ Hz

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Quizplus · Accepted Answer

The energy of the quantum of radiation is given as 1.3 keV, which is equivalent to 1.3 x 1.60 x 10^-16 J. Using the formula E = hν, where E is energy and h is Planck's constant, we can solve for frequency ν: ν = E/h. Substituting the values, ν = (1.3 x 1.60 x 10^-16 J) / (6.63 x 10^-34 J·s) = 3.1 x 10^17 Hz.

A Quantum of Radiation Has an Energy of 1