If a quantum of radiation has an energy of 3.0 keV, what is its wavelength? (h = 6.63 *10^-³⁴J.s, 1 eV = 1.60 *10^-¹⁹ J, c = 3.00 *10⁸ m/s, and 1 nm = 10^-⁹ m) A) 0.62 nm B) 0.32 nm C) 0.41 nm D) 1.02 nm

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Quizplus · Accepted Answer

To find the wavelength, use the formula E = hc/λ. First, convert 3.0 keV to joules: 3.0 keV = 3.0 x 10^3 eV = 3.0 x 10^3 x 1.60 x 10^-19 J = 4.8 x 10^-16 J. Then, rearrange the formula to λ = hc/E. Substitute the values: λ = (6.63 x 10^-34 J·s x 3.00 x 10^8 m/s) / 4.8 x 10^-16 J = 0.41 nm.

If a Quantum of Radiation Has an Energy of 3