Blue light ($\lambda$ = 460 nm) is incident on a piece of potassium (W = 2.45 eV). What is the maximum kinetic energy of the ejected photoelectrons? (h = 6.63 * 10^-³⁴ J.s, c = 3.00 * 10⁸ m/s, 1 eV = 1.60 *10^-¹⁹ J, and 1 nm = 10^-⁹ m) A) 1.0 eV B) 0.25 eV C) 0.50 eV D) 4.9 eV

Question

Quizplus · Accepted Answer

The Answer of Blue light ($\lambda$ = 460 nm) is incident on a piece of potassium (W = 2.45 eV). What is the maximum kinetic energy of the ejected photoelectrons? (h = 6.63 * 10^-³⁴ J.s, c = 3.00 * 10⁸ m/s, 1 eV = 1.60 *10^-¹⁹ J, and 1 nm = 10^-⁹ m) A) 1.0 eV B) 0.25 eV C) 0.50 eV D) 4.9 eV

Blue Light λ\lambdaλ = 460 Nm) Is Incident on a Piece of Potassium

Blue Light $\lambda$ = 460 Nm) Is Incident on a Piece of Potassium