A proton with mass 1.67 *10^-²⁷ kg moves in an accelerator with speed of 0.900c. What is its kinetic energy? (c = 3.00 * 10⁸m/s) A) 1.95 * 10^-¹⁰ J B) 1.00 * 10^-¹⁰ J C) 3.70 * 10^-¹⁰ J D) 1.35 *10^-¹⁰ J

Question

Quizplus · Accepted Answer

The correct answer is A because the kinetic energy of a particle is given by the equation K = (1/2)mv^2, where m is the mass of the particle and v is its speed. In this case, the mass of the proton is 1.67 x 10^-27 kg and its speed is 0.900c, where c is the speed of light. Plugging these values into the equation, we get K = (1/2)(1.67 x 10^-27 kg)(0.900c)^2 = 1.95 x 10^-10 J.

A Proton with Mass 1