Light of wavelength 610 nm is incident on a slit of width 0.20 mm, and a diffraction pattern is produced on a screen that is 2.0 m from the slit. What is the distance of the second dark fringe from the center of the central bright fringe? (1 nm = 10 ^- ⁹ m)

Question

Quizplus · Accepted Answer

The position of the dark fringes in a single-slit diffraction pattern is given by the formula $ y = \frac{m \lambda L}{a} $, where $ m $ is the order of the dark fringe, $ \lambda $ is the wavelength, $ L $ is the distance to the screen, and $ a $ is the slit width. For the second dark fringe ($ m = 2 $), $ y = \frac{2 \times 610 \times 10^{-9} \times 2}{0.20 \times 10^{-3}} \approx 0.0122 $ m or 1.22 cm, which is closest to 1.2 cm.

Light of Wavelength 610 Nm Is Incident on a Slit