A beam of light is incident upon a flat piece of glass (n = 1.50) at an angle of incidence of 60 $\degree$. Part of the beam is transmitted and part is reflected. What is the angle between the reflected and transmitted rays?

Question

Quizplus · Accepted Answer

The angle between the reflected and transmitted rays is given by the equation:$$	heta_r - 	heta_t = 	heta_i$$where $	heta_r$ is the angle of reflection, $	heta_t$ is the angle of transmission, and $	heta_i$ is the angle of incidence.In this case, $	heta_i = 60^\circ$ and $n = 1.50$. Using Snell's law, we can find $	heta_t$:$$n_1 \sin 	heta_i = n_2 \sin 	heta_t$$$$1.00 \sin 60^\circ = 1.50 \sin 	heta_t$$$$	heta_t = 38.6^\circ$$Therefore, the angle between the reflected and transmitted rays is:$$	heta_r - 	heta_t = 60^\circ - 38.6^\circ = 21.4^\circ$$The closest answer choice is A) 28°.

A Beam of Light Is Incident Upon a Flat Piece °\degree°

A Beam of Light Is Incident Upon a Flat Piece $\degree$