A series circuit contains a 12-V battery, a 4.0-$\Omega$resistor, and a 12-mH inductor. If the switch to the battery is closed at t = 0, find the time required for the current in the circuit to reach 63% of its final value.

Question

Quizplus · Accepted Answer

The time constant τ for an RL circuit is given by τ = L/R. Here, L = 12 mH and R = 4 Ω. So, τ = 12 mH / 4 Ω = 3 ms. The current reaches 63% of its final value in one time constant, which is 3 ms.

A Series Circuit Contains a 12-V Battery, a 4 Ω\OmegaΩ Resistor, and a 12-MH Inductor

A Series Circuit Contains a 12-V Battery, a 4 $\Omega$ Resistor, and a 12-MH Inductor