An electron is moving at a speed of 12 *106 m/s at an angle of 30° with respect to a uniform magnetic field of 8.0 * 10-4 T. What is the radius of the resulting helical path? (me = 9.11 * 10-31 kg, qe = 1.6 *10-19 C)
A) 2.1 cm
B) 3.7 cm
C) 4.3 cm
D) 8.5 cm
Correct Answer:
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