A solenoid with 500 turns, 0.10 m long, carrying a current of 2.0 A and with a radius of 10 ^- ²m will have what strength magnetic field at its center? (magnetic permeability in empty space µ₀ = 4 $\pi$ * 10 ^- ⁷T.m/A)

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid is given by B = µ₀ * (N/L) * I, where N is the number of turns, L is the length, and I is the current. Substituting the given values: B = (4π × 10⁻⁷ T·m/A) * (500/0.10 m) * 2.0 A = 1.3 × 10⁻² T.

A Solenoid with 500 Turns, 0 π\piπ * 10 - 7 T

A Solenoid with 500 Turns, 0 $\pi$ * 10 ^- ⁷T