If a metallic wire of cross-sectional area 3.0 *10 ^- ⁶ m² carries a current of 9.1 A and has a mobile charge density of 4.24 * 10²⁸ carriers/m³, what is the average drift velocity of the mobile charge carriers? (charge value = 1.6 *10 ^- ¹⁹ C) A) 3.4 * 10³ m/s B) 1.7 * 10³ m/s C) 4.5*10 ^- ⁴ m/s D) 1.5 *10 ^- ⁴ m/s

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Quizplus · Accepted Answer

The average drift velocity (v_d) can be calculated using the formula: v_d = I / (n * A * e), where I is the current, n is the charge density, A is the cross-sectional area, and e is the charge of an electron. Substituting the given values: v_d = 9.1 / (4.24 x 10^28 * 3.0 x 10^-6 * 1.6 x 10^-19) = 4.5 x 10^-4 m/s.

If a Metallic Wire of Cross-Sectional Area 3