Two resistors of values 6.0 and 12.0 $\Omega$ are connected in parallel. This combination in turn is hooked in series with an 8.0-$\Omega$ resistor and a 24-V battery. What is the current in the 12-$\Omega$ resistor?
A) 1.3 A
B) 4.0 A
C) 12 A
D) 0.67 A

Question

Quizplus · Accepted Answer

The equivalent resistance of the parallel resistors (6Ω and 12Ω) is 4Ω. The total resistance in series with the 8Ω resistor is 12Ω. The total current from the battery is 24V/12Ω = 2A. The current through the 12Ω resistor in parallel is 2A * (6Ω / (6Ω + 12Ω)) = 0.67A.

Two Resistors of Values 6 Ω\OmegaΩ Are Connected in Parallel Ω\OmegaΩ Resistor and a 24-V Battery

Two Resistors of Values 6 $\Omega$ Are Connected in Parallel $\Omega$ Resistor and a 24-V Battery