Case 1: An electron is released from rest in a uniform electric field. Case 2: A proton is released from rest in a uniform electric field of the same magnitude as in case 1. How does the electric potential energy of the charge-field system behave in these cases?

Question

Quizplus · Accepted Answer

The electric potential energy of a charge-field system is given by the equation U = qV, where q is the charge and V is the electric potential. In case 1, the electron has a negative charge, so its potential energy will decrease as it moves in the electric field. In case 2, the proton has a positive charge, so its potential energy will increase as it moves in the electric field.

Case 1: an Electron Is Released from Rest in a Uniform