A proton (+1.6 *10 ^- ¹⁹ C) moves 10 cm on a path in the direction opposite to a uniform electric field of strength 3.0 N/C. How much work is done on the proton by the electrical field?

Question

Quizplus · Accepted Answer

The work done by the electric field is calculated using the formula W = -qEd, where q is the charge, E is the electric field strength, and d is the distance. Since the proton moves opposite to the field, the work done is negative: W = -(1.6 x 10^-19 C)(3.0 N/C)(0.1 m) = -4.8 x 10^-20 J.

A Proton (+1