A 6.0-mC charge is placed at the origin and a second charge is placed on the x axis at x = 0.30 m. If the resulting force on the second charge is 5.4 N in the positive x direction, what is the value of its charge?

Question

Quizplus · Accepted Answer

The force between two charges is given by Coulomb's law: F = k * |q1 * q2| / r^2. Given F = 5.4 N, q1 = 6.0 mC = 6.0 x 10^-3 C, r = 0.30 m, and k = 8.99 x 10^9 N m^2/C^2, solving for q2 gives q2 = 9.0 x 10^-9 C = 9.0 nC.

A 60-MC Charge Is Placed at the Origin and a Second