A 20-kg piece of aluminum (which has a specific heat of 900 J/kg ·$\degree$C) is warmed so that its temperature increases by 5.0$\degree$C. How much heat was transferred into it?

Question

Quizplus · Accepted Answer

The heat transferred (Q) can be calculated using the formula Q = mcΔT, where m is the mass (20 kg), c is the specific heat capacity (900 J/kg°C), and ΔT is the temperature change (5°C). Q = 20 kg * 900 J/kg°C * 5°C = 90,000 J or 9.0 × 10^4 J.

A 20-Kg Piece of Aluminum (Which Has a Specific Heat °\degree°

A 20-Kg Piece of Aluminum (Which Has a Specific Heat $\degree$