A windowpane is half a centimeter thick and has an area of 2.0 m². The temperature difference between the inside and outside surfaces of the pane is 15$\degree$C. What is the rate of heat flow through this window? (Thermal conductivity for this glass is 0.84 W / m ·$\degree$C.) A) 5000 J/s B) 2500 J/s C) 1300 J/s D) 630 J/s

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The rate of heat flow through a windowpane is given by the equation:Q = k * A * (T1 - T2) / dwhere:Q is the rate of heat flow in wattsk is the thermal conductivity of the glass in W / m · °CA is the area of the windowpane in m2T1 is the temperature of the inside surface of the windowpane in °CT2 is the temperature of the outside surface of the windowpane in °Cd is the thickness of the windowpane in mIn this problem, we are given the following information:k = 0.84 W / m · °CA = 2.0 m2T1 = 20 °CT2 = 5 °Cd = 0.5 cm = 0.005 mPlugging these values into the equation, we get:Q = 0.84 W / m · °C * 2.0 m2 * (20 °C - 5 °C) / 0.005 mQ = 5040 WTherefore, the rate of heat flow through the windowpane is 5040 W, which is closest to answer choice A, 5000 J/s.

A Windowpane Is Half a Centimeter Thick and Has an Area