The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.160 m) cos ( $\pi$t/16). What is its position at t = 6.0 s?
A) 0.160 m
B) 0.159 m
C) 0.061 m
D) 0.089 m

Question

Quizplus · Accepted Answer

To find the position at t = 6.0 s, substitute t = 6.0 s into the equation x = (0.160 m) cos (πt/16). This gives x = (0.160 m) cos (π * 6.0 / 16) = (0.160 m) cos (0.375π). Calculating this gives approximately x = 0.061 m.

The Position of a 0 π\piπ T/16) What Is Its Position at T = 6

The Position of a 0 $\pi$ T/16) What Is Its Position at T = 6