A 0.20-kg object is attached to a spring with spring constant k = 10 N/m and moves with simple harmonic motion over a horizontal, frictionless surface. At the instant that it is displaced from equilibrium by -0.060 m, what is its acceleration? A) "360 m/s²" B) "-30 m/s²" C) "3.0 m/s²" D) "0.18 m/s²"

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Quizplus · Accepted Answer

The acceleration in simple harmonic motion is given by a = -kx/m. Here, k = 10 N/m, x = 0.060 m, and m = 0.20 kg. So, a = -(10 * 0.060) / 0.20 = -3.0 m/s².

A 020-Kg Object Is Attached to a Spring with Spring Constant