The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.120 m) cos ( $\pi$t/16). What is the maximum net force on the mass as it oscillates? A) 0.98 *10^-³ N B) 7.4 *10^-³ N C) 3.0 * 10^-³ N D) 4.7 N

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The Answer of The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.120 m) cos ( $\pi$t/16). What is the maximum net force on the mass as it oscillates? A) 0.98 *10^-³ N B) 7.4 *10^-³ N C) 3.0 * 10^-³ N D) 4.7 N

The Position of a 0 π\piπ T/16) What Is the Maximum Net Force on the Mass

The Position of a 0 $\pi$ T/16) What Is the Maximum Net Force on the Mass