A baseball pitcher loosens up his pitching arm. He tosses a 0.20-kg ball using only the rotation of his forearm, 0.32 m in length, to accelerate the ball. What is the moment of inertia of the ball alone as it moves in a circular arc with a radius of 0.32 m? A) 1.5 *10^-² kg·m² B) 2.0 *10^-² kg·m² C) 4.0 *10^-² kg·m² D) 7.6 *10^-²kg·m²

Question

Quizplus · Accepted Answer

The moment of inertia (I) for a point mass moving in a circular path is given by I = m*r^2. Here, m = 0.20 kg and r = 0.32 m. So, I = 0.20 * (0.32)^2 = 0.02048 kg·m^2, which matches option B.

A Baseball Pitcher Loosens Up His Pitching Arm