Preston pushes a wheelbarrow weighing 500 N to the top of a 50.0-m ramp, inclined at 20.0 $\degree$ with the horizontal and leaves it. Tamara accidentally bumps the wheelbarrow. It slides back down the ramp, during which a 60.0-N frictional force acts on it over the 50.0 m. What is the wheelbarrow's kinetic energy at the bottom at of the ramp? (g = 9.8 m/s²) A) 5550 J B) 6550 J C) 8150 J D) 13,100 J

Question

Quizplus · Accepted Answer

The gravitational potential energy at the top is converted into kinetic energy at the bottom minus the work done against friction. Potential energy = mgh = 500 N * 50 m * sin(20°) = 1710 J. Work done against friction = 60 N * 50 m = 3000 J. Kinetic energy = 1710 J - 3000 J = 5550 J.

Preston Pushes a Wheelbarrow Weighing 500 N to the Top °\degree°

Preston Pushes a Wheelbarrow Weighing 500 N to the Top $\degree$