A trapeze artist, with swing, weighs 700 N; he is momentarily held to one side by his partner so that the swing ropes make an angle of 30.0 $\degree$ with the vertical. In such a condition of static equilibrium, what is the horizontal force being applied by the partner?
A) 924 N
B) 404 N
C) 808 N
D) 233 N

Question

Quizplus · Accepted Answer

The horizontal force can be found using the component of the weight that acts horizontally. The horizontal force is equal to the weight times the sine of the angle: 700 N * sin(30°) = 350 N. However, the correct calculation should be 700 N * tan(30°) = 404 N.

A Trapeze Artist, with Swing, Weighs 700 N; He Is °\degree°

A Trapeze Artist, with Swing, Weighs 700 N; He Is $\degree$