A stone is thrown at an angle of 30 $\degree$ above the horizontal from the top edge of a cliff with an initial speed of 14 m/s. A stop watch measures the stone's trajectory time from top of cliff to bottom to be 7.1 s. How far out from the cliff's edge does the stone travel horizontally? Note: g = 9.8 m/s²and air resistance is negligible. A) 58 m B) 68 m C) 86 m D) 197 m

Question

Quizplus · Accepted Answer

The horizontal distance can be calculated using the formula: distance = horizontal velocity * time. The horizontal velocity is the initial speed multiplied by the cosine of the angle (14 m/s * cos(30°)). The time is given as 7.1 s. Calculating this gives approximately 86 m.

A Stone Is Thrown at an Angle of 30 °\degree° Above the Horizontal from the Top Edge of a Cliff

A Stone Is Thrown at an Angle of 30 $\degree$ Above the Horizontal from the Top Edge of a Cliff