A stone is thrown with an initial speed of 15 m/s at an angle of 53 $\degree$ above the horizontal from the top of a 40-m building. If g = 9.8 m/s²and air resistance is negligible, then what is the magnitude of the vertical velocity component of the rock as it hits the ground? A) 30 m/s B) 24 m/s C) 26 m/s D) 29 m/s

Question

Quizplus · Accepted Answer

The vertical velocity component can be found using the kinematic equation: v_y^2 = u_y^2 + 2gh, where u_y is the initial vertical velocity (15*sin(53°)), g is the acceleration due to gravity, and h is the height of the building. Solving gives approximately 30 m/s.

A Stone Is Thrown with an Initial Speed of 15 °\degree°

A Stone Is Thrown with an Initial Speed of 15 $\degree$