Wiley Coyote has missed the elusive Road Runner once again.This time,he leaves the edge of the cliff at 40.0 m/s horizontal velocity.If the canyon is 100 m deep,how far from his starting point on the edge of the cliff does the coyote land?
A) 207 m
B) 247 m
C) 339 m
D) 400 m

Question

Quizplus · Accepted Answer

The correct answer is A because the horizontal velocity is constant, so the horizontal displacement is simply the velocity multiplied by the time it takes to fall 100 m. The time it takes to fall 100 m is given by:$$t = \sqrt{\frac{2d}{g}}$$where d is the distance fallen and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get:$$t = \sqrt{\frac{2(100 \ m)}{9.8 \ m/s^2}} = 4.52 \ s$$The horizontal displacement is then:$$d = vt = (40.0 \ m/s)(4.52 \ s) = 207 \ m$$

Wiley Coyote Has Missed the Elusive Road Runner Once Again