When 3-heptanone is treated with 2 equivalents of 1-butanol in the presence of sulfuric acid,the product is the compound shown below. 
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Q94: Oxidation of the aldehyde below gives the
Q95: In a process similar to the one
Q96: When the compound shown is treated with
Q97: The compound 2-methyl-2-pentanol is oxidized to produce
Q98: The alcohol below has a higher boiling
Q100: The compound below is soluble in water
Q101: The simplest aldehyde contains _ carbon atom(s),and
Q102: Ketones are reduced to _.
Q103: _ is the simplest aldehyde.
Q104: Aldehydes are identified by the suffix _,and
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