What is the molarity of an HCl solution if 43.6 mL of a 0.125 M KOH solution are needed to titrate a 25.0 mL sample of the acid according to the equation below? KOH(aq)+ HCl(aq)→ H₂O(l)+ KCl(aq)

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Quizplus · Accepted Answer

The molarity of the HCl solution can be calculated using the titration formula: M1V1 = M2V2, where M1 and V1 are the molarity and volume of the HCl solution, and M2 and V2 are the molarity and volume of the KOH solution. Given that M2 = 0.125 M and V2 = 43.6 mL for KOH, and V1 = 25.0 mL for HCl, we can solve for M1 (HCl's molarity). Rearranging the formula gives M1 = (M2V2) / V1 = (0.125 M * 43.6 mL) / 25.0 mL = 0.218 M.

What Is the Molarity of an HCl Solution If 43