What is the molarity of a 11.5% (w/v)glucose (C₆H₁₂O₆,molar mass 180.16 g/mol)solution?

Question

Quizplus · Accepted Answer

A 11.5% (w/v) glucose solution means 11.5 g of glucose is dissolved in 100 mL of solution. To find molarity (moles of solute per liter of solution), divide the mass of glucose by its molar mass and then by the volume of solution in liters. $ \frac{11.5\,g}{180.16\,g/mol} \approx 0.0638\,mol $ in 0.1 L, so $ \frac{0.0638\,mol}{0.1\,L} = 0.638\,M $.

What Is the Molarity of a 11