Consider the combustion reaction of propane: C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g) ,where ΔH = -531 kcal. If 1.24 × 105 kcal of energy is released in the reaction,how many moles of propane were burned?
A) 234 mol of C3H8
B) 6.58 × 107 mol of C3H8
C) 0.00428 mol of C3H8
D) 0.0179 mol of C3H8
Correct Answer:
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