In a reversible chemical reaction at equilibrium,the concentration of X (the reactant)is 0.75 mol/L,and the concentration of Y (the product)is 2.25 mol/L.At 25°C,what would be the K_eq? A)0.33 B)3.0 C)1.69 D)1.50 E)37.5

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The equilibrium constant (K) for a reversible reaction is given by the ratio of the concentration of the products to the reactants, raised to the power of their stoichiometric coefficients. Assuming a simple reaction where X converts to Y (X ⇌ Y), the equilibrium constant expression would be K = [Y]/[X]. Substituting the given concentrations, K = 2.25 / 0.75 = 3.0.

In a Reversible Chemical Reaction at Equilibrium,the Concentration of X