In a cell,the concentration of glucose-6-phosphate is 83 ?M and of fructose-6-phosphate is 14 ?M.The ?G°' = 410 cal/mol for the conversion of glucose-6-phosphate to fructose-6-phosphate.Based upon this information,the ?G' for this reaction (in cal/mol)is
A)?644.
B)?63.7.
C)0.
D)27.
E)644.

Question

Quizplus · Accepted Answer

The Gibbs free energy change (?G') can be calculated using the equation: ?G' = ?G°' + RT ln([products]/[reactants]). Substituting the given values, ?G' = 410 + (1.987 * 298 * ln(14/83)) = -644 cal/mol.

In a Cell,the Concentration of Glucose-6-Phosphate Is 83 ?M and of Fructose-6-Phosphate