A power transmission line carries 400A of current at a voltage of 765 kV.If the line has a resistance of 29 µΩ/m, what is the rate at which energy is being dissipated in 800 km of line?
A)0 W
B)3.7 kW
C)310 kW
D)3.7 MW
E)310 MW

Question

Quizplus · Accepted Answer

The power dissipated in the line can be calculated using the formula P = I^2 * R, where I is the current and R is the total resistance. The total resistance R is the resistance per meter times the length of the line: R = 29 µΩ/m * 800,000 m = 23.2 Ω. Thus, P = (400 A)^2 * 23.2 Ω = 3.7 MW.

A Power Transmission Line Carries 400A of Current at a Voltage