You are facing a loop of wire which carries a clockwise current of 3.0 A and which surrounds an area of 5.8 x 10^?2m².The magnetic dipole moment of the loop is: A)3.0 A.m², into the page B)3.0 A.m², out of the page C)0.17 A.m², into the page D)0.17 A.m², out of the page E)0.17 A.m², left to right

Question

Quizplus · Accepted Answer

The magnetic dipole moment of a current loop is defined as the product of the current and the area enclosed by the loop, multiplied by a unit vector perpendicular to the plane of the loop. Mathematically, we can express this as:

$\vec{\mu} = I \vec{A} 	imes \hat{n}$

where I is the current, $\vec{A}$ is the area vector, and $\hat{n}$ is a unit vector perpendicular to the plane of the loop.

In this case, the current is 3.0 A and the area enclosed by the loop is 5.8 x 10^-2 m^2. The direction of the magnetic dipole moment is given by the right-hand rule: if you curl your fingers in the direction of the current, your thumb will point in the direction of the magnetic dipole moment.

Since the current is clockwise (i.e., it flows in the direction of your fingers if you curl your right hand around the loop), the magnetic dipole moment will point into the page if your thumb is pointing up (i.e., in the direction of $\hat{n}$).

Thus, the answer is (C) 0.17 A m^2, into the page.

You Are Facing a Loop of Wire Which Carries a Clockwise