A battery with an emf of 12 V and an internal resistance of 1 $\Omega$ is used to charge a battery with an emf of 10 V and an internal resistance of 1 $\Omega$.The current in the circuit is:
A)1 A
B)2 A
C)4 A
D)11 A
E)22 A

Question

Quizplus · Accepted Answer

The net emf in the circuit is 12 V - 10 V = 2 V. The total resistance in the circuit is 1 Ω + 1 Ω = 2 Ω. Using Ohm's law (V = IR), the current I = 2 V / 2 Ω = 1 A.

A Battery with an Emf of 12 V and an Internal