A wire has an electric field of 6.2 V/m and carries a current density of 2.4 x 10⁸ A/m².What is its resistivity? A)6.7 x 10^-10 $\Omega$.m B)1.5 x 10^-8 $\Omega$.m C)2.6 x 10^-8 $\Omega$.m D)3.9 x 10⁷ $\Omega$.m E)1.5 x 10⁹ $\Omega$.m

Question

Quizplus · Accepted Answer

The resistivity of the wire can be calculated using the formula:

ρ = E / J

where ρ is the resistivity, E is the electric field, and J is the current density.

Plugging in the given values:

ρ = 6.2 V/m / (2.4 x 10^18 A/m^2)

ρ = 2.6 x 10^-8 Ω·m

Therefore, the best choice is C.

A Wire Has an Electric Field of 6 Ω\OmegaΩ M B)15 X 10-8

A Wire Has an Electric Field of 6 $\Omega$ M
B)15 X 10^-8