A certain x-ray tube requires a current of 7 mA at a voltage of 80 kV.The rate of energy dissipation is:
A)5600 W
B)560 W
C)26 W
D)11.4 W
E)0.088 W

Question

Quizplus · Accepted Answer

The rate of energy dissipation in an electrical device is given by the formula Power (P) = Voltage (V) * Current (I). Here, the voltage is 80 kV (which is 80,000 V) and the current is 7 mA (which is 0.007 A). Therefore, P = 80,000 V * 0.007 A = 560 W.

A Certain X-Ray Tube Requires a Current of 7 MA