The coefficient of static friction between a certain cylinder and a horizontal floor is 0.40.If the rotational inertia of the cylinder about its symmetry axis is given by I = (1/2)MR², then the maximum acceleration the cylinder can have without sliding is: A)0.1 g B)0.2 g C)0.4 g D)0.8 g E)1.0 g

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The Answer of The coefficient of static friction between a certain cylinder and a horizontal floor is 0.40.If the rotational inertia of the cylinder about its symmetry axis is given by I = (1/2)MR², then the maximum acceleration the cylinder can have without sliding is: A)0.1 g B)0.2 g C)0.4 g D)0.8 g E)1.0 g

The Coefficient of Static Friction Between a Certain Cylinder and a Horizontal