A 100-kg piano rolls down a 20° incline.A man tries to keep it from accelerating, and manages to keep its acceleration to 1.2 m/s².If the piano rolls 5 m, what is the net work done on it by all the forces acting on it?

Question

Quizplus · Accepted Answer

First, we need to find the total force acting on the piano while it rolls down the incline. We can use the formula:

force = mass x acceleration

The mass of the piano is 100 kg, and the acceleration is given as 1.2 m/s^2. Therefore, the force is:

force = 100 kg x 1.2 m/s^2 = 120 N

Next, we need to find the work done by this force over a distance of 5 m. We can use the formula:

work = force x distance x cos(theta)

where theta is the angle between the force and the displacement. Since the force and the displacement are in the same direction, we can simplify this to:

work = force x distance

Plugging in the values, we get:

work = 120 N x 5 m = 600 J

Therefore, the net work done on the piano by all the forces acting on it is 600 J, which corresponds to choice letter C.

A 100-Kg Piano Rolls Down a 20° Incline