An object moves from x = -2.1 m, y = 3.7 m to x = 3.3 m, y = -1.1 m in a time of 5.3 s.What is its average velocity?
A)7.2 m/s, 32° below the positive x-axis
B)2.5 m/s, 48° below the positive x-axis
C)1.4 m/s, 42° below the positive x-axis
D)4.9 m/s, 76° below the positive x-axis
E)0.92 m/s, 14° below the positive x-axis

Question

Quizplus · Accepted Answer

The average velocity is calculated by finding the displacement vector and dividing by the time. The displacement is (3.3 - (-2.1), -1.1 - 3.7) = (5.4, -4.8). The magnitude of this vector is √(5.4² + (-4.8)²) = 7.2 m. The average velocity is 7.2 m / 5.3 s = 1.4 m/s. The angle is tan⁻¹(4.8/5.4) = 42° below the positive x-axis.

An Object Moves from X = -2