Assuming that the user inputs "twenty" as the input, what is the output of the following code snippet? String numEmployeesStr;
Scanner in = new Scanner(System.in) ;
System.out.println("Please enter the number of your employees: ") ;
NumEmployeesStr = in.next() ;
Int numEmployees = Integer.parseInt(numEmployeesStr) ;
If (numEmployees < 10)
{
System.out.println("Very small business!") ;
}
Else
{
System.out.println("Small business") ;
If (numEmployees > 100)
{
System.out.println("Mid size business") ;
}
Else
{
System.out.println("Large business") ;
}
}

Question

Assuming that the user inputs "twenty" as the input, what is the output of the following code snippet? String numEmployeesStr;
Scanner in = new Scanner(System.in);
System.out.println("Please enter the number of your employees: ");
NumEmployeesStr = in.next();
Int numEmployees = Integer.parseInt(numEmployeesStr);
If (numEmployees < 10)
{
System.out.println("Very small business!");
}
Else
{
System.out.println("Small business");
If (numEmployees > 100)
{
System.out.println("Mid size business");
}
Else
{
System.out.println("Large business");
}
}
A) Very small business!
B) Small business
C) Mid size business
D) Run-time error

Quizplus · Accepted Answer

The code will throw a run-time error because "twenty" is not a valid integer and cannot be parsed by Integer.parseInt().

Assuming That the User Inputs "Twenty" as the Input, What