Insert the missing code in the following code fragment. This fragment is intended to read binary data. public static void main(String[] args) throws IOException
{
String address = "http://horstmann.com/bigjava.gif";
URL imageLocation = new URL(address);
InputStream in = _________;
) . .
}
A) new Scanner("http://horstmann.com/bigjava.gif")
B) new Scanner(imageLocation)
C) new imageLocation.openStream
D) imageLocation.openStream()

Question

Quizplus · Accepted Answer

The correct method to open a stream from a URL object in Java is to call the `openStream()` method on the URL object, which returns an InputStream.

Insert the Missing Code in the Following Code Fragment