If the Sun converts 5 * 10¹¹ kg of H to He per second and the mass of a single hydrogen nucleus is 1.7 * 10^-²⁷ kg, how many net proton-proton reactions go on per second in the Sun? What is the luminosity produced if the mass difference between a single helium nucleus and four hydrogen nuclei is 4 *10^-²⁹ kg? Note that 1 watt =1 m² kg/s³.

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Quizplus · Accepted Answer

The number of reactions per second is (5 F1F1F1S1F1F1F10 10¹¹ kg/s) / (1.7 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10²⁷ kg) = 3 F1F1F1S1F1F1F10 10³⁸ reactions/s. The luminosity is (4 F1F1F1S1F1F1F10 10F1F1F1S1^F1F1F10²⁹ kg) * (3 F1F1F1S1F1F1F10 10³⁸ reactions/s) * (1 m² kg/s³) / (1 watt) = 4 F1F1F1S1F1F1F10 10²⁶ watts.

If the Sun Converts 5 * 1011 Kg of H

If the Sun Converts 5 * 10¹¹ Kg of H