If a beam of electromagnetic radiation has an intensity of 120 W/m²,what is the maximum value of the electric field? (c = 3.0 × 10⁸ m/s,μ₀ = 4π × 10^-7 T ∙ m/A, ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A)1.5 kV/m B)1.0 µT C)1.0 µV/m D)0.30 kV/m E)0.0032 V/m

Question

Quizplus · Accepted Answer

The intensity of the electromagnetic radiation is given by:

$I = \frac{1}{2}c\epsilon_0E^2$

where $I$ is the intensity, $c$ is the speed of light, $\epsilon_0$ is the electric constant, and $E$ is the electric field.

Rearranging this equation to solve for $E$ yields:

$E = \sqrt{\frac{2I}{c\epsilon_0}}$

Plugging in the given values, we get:

$E = \sqrt{\frac{2(120	ext{ W/m}^2)}{(3.0	imes 10^8	ext{ m/s})(8.85	imes 10^{-12}	ext{ C}^2/	ext{N}\cdot	ext{m}^2)}} \approx 0.30 	ext{ kV/m}$

Therefore, the answer is D: 0.30 kV/m.

If a Beam of Electromagnetic Radiation Has an Intensity of 120