Assuming the radius of diatomic molecules is approximately
for what pressure will the mean free path in room-temperature (20°C) nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10-23 J/K, Avogadro's number is 6.02 × 1023 molecules/mole, and the ideal gas constant is
= 0.0821 L ∙ atm/mol ∙ K.
A) 4.9 × 10-8 atm
B) 6.9 × 10-8 atm
C) 1.5 × 10-7 atm
D) 2.2 × 10-7 atm
Correct Answer:
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