The position of an object that is oscillating on an ideal spring is given by the equation x = (12.3 cm)cos[(1.26s^-1)t].At time t = 0.815 s,
(a)how fast is the object moving?
(b)what is the magnitude of the acceleration of the object?

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The Answer of The position of an object that is oscillating on an ideal spring is given by the equation x = (12.3 cm)cos[(1.26s^-1)t].At time t = 0.815 s, (a)how fast is the object moving? (b)what is the magnitude of the acceleration of the object?

The Position of an Object That Is Oscillating on an Ideal