Consider the following reaction.How much heat is released if 5.00 moles of potassium react with excess chlorine? 2 K (s)+ Cl₂ (g)$\rightarrow$ 2 KCl (g)$\Delta$H_rxn = -873.0 kJ

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The reaction shows that 2 moles of potassium react to release 873.0 kJ of heat. For 5 moles of potassium, the heat released would be (5 moles / 2 moles) * -873.0 kJ = -2,182.5 kJ, which rounds to -2,180 kJ, matching option D.

Consider the Following Reaction →\rightarrow→ 2 KCl (G) Δ\DeltaΔ Hrxn = -873

Consider the Following Reaction $\rightarrow$ 2 KCl (G) $\Delta$ H_rxn = -873