Consider the following reaction: 4 Fe + 3 O₂ $\rightarrow$ 2 Fe₂O₃
If 44.2 grams of oxygen react with an excess of iron,what mass of Fe₂O₃can form?
(Fe₂O₃ = 159.70 g/mol)

Question

Consider the following reaction: 4 Fe + 3 O₂ $\rightarrow$ 2 Fe₂O₃ If 44.2 grams of oxygen react with an excess of iron,what mass of Fe₂O₃can form? (Fe₂O₃ = 159.70 g/mol)

Quizplus · Accepted Answer

First, identify the correct chemical formula from the question's formatting issues: the product is Fe2O3. Given the molar mass of Fe2O3 is 159.70 g/mol, and using the stoichiometry of the reaction, we calculate the mass of Fe2O3 formed from 44.2 grams of O2. Since O2 has a molar mass of approximately 32 g/mol, 44.2 grams of O2 is about 1.38 moles. The reaction stoichiometry (4 Fe + 3 O2 → 2 Fe2O3) shows that 3 moles of O2 produce 2 moles of Fe2O3. Therefore, 1.38 moles of O2 would produce about 0.92 moles of Fe2O3, which equals 147 grams (0.92 moles * 159.70 g/mol).

Consider the Following Reaction: 4 Fe + 3 O2 →\rightarrow→ 2 Fe2O3 If 44

Consider the Following Reaction: 4 Fe + 3 O₂ $\rightarrow$ 2 Fe₂O₃
If 44