Table $8.3$
A company uses a kanban system. The daily demand for part $A$ is 4000 units. The average waiting time for a container of parts is $0.2$ day. The processing time for a container of part $A$ is $0.8$ day, and a container holds 300 units.
-Use the information in Table 8.3. How many kanban containers would be required if a 5 % efficiency factor is used?
A) 10 or less
B) 11 or 12
C) 13 or 14
D) 15 or more

Question

Quizplus · Accepted Answer

The number of kanban containers is calculated using the formula: $ \text{Number of Kanbans} = \frac{D \times (W + P) \times (1 + \text{Efficiency Factor})}{C} $, where $D$ is daily demand, $W$ is waiting time, $P$ is processing time, and $C$ is container size. Plugging in the values: $ \frac{4000 \times (0.2 + 0.8) \times 1.05}{300} = 14 $.

Table 8.38.38.3 A Company Uses a Kanban System AAA Is 4000 Units 0.20.20.2

Table $8.3$ A Company Uses a Kanban System $A$ Is 4000 Units $0.2$