Table 10.3
A firm has the following demand forecasts for the five markets that it serves:
$$\begin{array} { | c | c | c | }
\hline \text { Market } & \text { Coordinates } & \begin{array} { c }
\text { Demand } \
\text { Forecast }
\end{array} \
\hline \text { A } & ( 3,1 ) & 10 \
\text { B } & ( 12,9 ) & 12 \
\text { C } & ( 9,14 ) & 9 \
\text { D } & ( 8,8 ) & 4 \
\text { E } & ( 2,10 ) & 15 \
\hline
\end{array}$$
-Use the information in Table 10.3. If the firm decides to locate the warehouse at point D, what is the total load- distance score? (Use rectilinear distance).
A) less than 400
B) between 401 and 450
C) between 451 and 500
D) more than 500

Question

Table 10.3
A firm has the following demand forecasts for the five markets that it serves:
$$\begin{array} { | c | c | c | } 
\hline \text { Market } & \text { Coordinates } & \begin{array} { c } 
\text { Demand } \
\text { Forecast }
\end{array} \
\hline \text { A } & ( 3,1 ) & 10 \
\text { B } & ( 12,9 ) & 12 \
\text { C } & ( 9,14 ) & 9 \
\text { D } & ( 8,8 ) & 4 \
\text { E } & ( 2,10 ) & 15 \
\hline
\end{array}$$
-Use the information in Table 10.3. If the firm decides to locate the warehouse at point D, what is the total load- distance score? (Use rectilinear distance).
A) less than 400
B) between 401 and 450
C) between 451 and 500
D) more than 500

Quizplus · Accepted Answer

The total load-distance score is the sum of the distances from each market to the warehouse multiplied by the demand forecast for that market. Using rectilinear distance, the distance from market A to warehouse D is |3-8| + |1-8| = 10. The distance from market B to warehouse D is |12-8| + |9-8| = 4. The distance from market C to warehouse D is |9-8| + |14-8| = 6. The distance from market E to warehouse D is |2-8| + |10-8| = 6. The total load-distance score is 10*10 + 12*4 + 9*6 + 4*6 + 15*6 = 400.

Table 103 a Firm Has the Following Demand Forecasts for the the Five

Table 103
a Firm Has the Following Demand Forecasts for the the Five